Time, Speed and Distance: Formulas, Trains and Boats
The essential relationships between time, speed and distance, with quick methods for average speed, train problems and boats in streams.
These questions look varied but rest on one relationship: distance = speed × time.
The basics
- Speed = distance ÷ time
- Time = distance ÷ speed
- Distance = speed × time
Unit conversion
- km/h to m/s: multiply by 5/18.
- m/s to km/h: multiply by 18/5.
Example: 72 km/h = 72 × 5/18 = 20 m/s.
Average speed
For a journey with equal distances at speeds x and y:
Average speed = 2xy ÷ (x + y)
Example: going at 40 km/h and returning at 60 km/h gives 2 × 40 × 60 ÷ 100 = 48 km/h, not 50.
If the times are equal, the average is simply (x + y) ÷ 2.
Relative speed
- Same direction: subtract the speeds.
- Opposite directions: add the speeds.
Trains
- Crossing a pole or a person: time = length of train ÷ speed.
- Crossing a platform or bridge: time = (train length + platform length) ÷ speed.
- Two trains crossing: use the sum of lengths and the relative speed.
Example: a 150 m train at 54 km/h crosses a pole in 150 ÷ 15 = 10 seconds, since 54 km/h = 15 m/s.
Boats and streams
Let boat speed in still water be u and stream speed be v.
- Downstream speed = u + v
- Upstream speed = u − v
- Boat speed = (downstream + upstream) ÷ 2
- Stream speed = (downstream − upstream) ÷ 2
Common traps
- Units. Convert to consistent units first.
- Average speed. Do not take a simple average when distances are equal.
- Train length. Remember to add lengths when crossing another object with length.
Tips
- Draw a quick sketch for train and boat questions.
- Write the unit beside each number.
- Check that the answer is realistic.
Practice
Regular short sets on this topic quickly build confidence, because the same few ideas repeat.
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